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2G1
14 continued Understand and
apply the formula relating transformer primary and
secondary turns to primary and secondary potential
differences and currents. Maths formula also most
certain to be used in this question !!! The formulae are : Here we are dealing with AC as we are considering transformers! Transformers and potential differences In the formulae : V_{p }= Volts in the primary coil (or the driven coil) V_{s} = Volts in the secondary coil N_{p }= Number of turns in the primary coil N_{s }= Number of turns in the secondary coil I_{p} = current passing in the primary coil I_{s} = Current passing in the secondary coil Rearranging the formula to it is a little easier to see that the ratio of the input voltage output voltage it equal to the ratio of the input turns divided by the output turns This is a simple comparison of input and output. From the above it is possible to calculate the transformation of voltage from the primary to the secondary such as you would need to do if building a power supply. the part Ns / Np is called the turns ratio and was introduced to you in the Intermediate Licence course click to check back. Example: A transformer has 200 turns on the primary and 100 on the secondary and an input voltage of 50 volts. What is the calculated output voltage ? applying the figures to the formula V_{s} = 50 x 100/200 answer 25 volts. Transformers and currents Rearranging the formula to it is a little easier to see that the ratio of the input current output current it equal to the ratio of the output turns divided by the input turns. This is not quite so straight forward but is based on the Power equation P = V x I. Thus what is put in as power one side (V_{in }x I_{n}), assuming no losses will come out as power the other (V_{out} x I_{out}). This leads to the equation The equation says that the current in the primary the current in the secondary is dependent upon ratio of secondary turns primary turns. Putting some figures to this if there is 240 volts on the primary of 100 turns and 24 volts at 10 amps on the secondary  there would be less current at 240 Volts in the primary. With this in mind let's work it out. From the equation then 24 / 240 = N_{s} / 100 From the equation then N_{s} = 24 x 100 /240 answer = 10 turns N_{s} so I_{p} / 10 = 10 / 100 thus I_{p} = 10 x 10 / 100 answer 1 amp If you were given the current that can be supplied from the primary you can find out what current can be taken from the secondary such as you would need to do if building a power supply if you know the turns ratio. So now using this formula Example: A transformer can allow a secondary coil current of a maximum of 20 amps and it has 400 turns on the primary and 100 on the secondary what is the required input current capability ? Applying the figures to the formula I_{p} = 20 x 100 / 400 answer 5 amps.
2G1 14 Understand the impedance change in a transformer and apply formula relating transformer primary and secondary turns to primary and secondary impedances. The formula is : Matching input and output impedances In a perfect situation one without reactance losses or leakages the above equation would hold true where:
The primary terminal impedance is determined by the equation being dependent only upon the load resistance and the turns ratio. Where would this be used? Say a AF amplifier required a load of 200ohms to operate properly and you are driving an 8ohm speaker then you could, assuming a perfect world, design an impedance transformer to ensure the criteria was met. by dividing both side by Z_{s} we get by taking the square root of both sides we get = = 5So the primary turns must be 5 times as many as the secondary. This impedance matching means altering the "load" impedance by the transformer to the required output level.
Not in the Full 2021 syllabus Understand the cause and effects of eddy currents and the need for laminations (or ferrites) in transformers. Eddy Currents When an AC supply passes through a coil, a magnetic field is generated. The size or density of the magnetic field can be increased by the use of an iron core such as is used in transformers. Iron being a conductor, the magnetic field causes an electric current to flow in the core. The current flow is called "EDDY CURRENTS". Effect of the eddy currents The effect of the eddy currents is a loss of power, as flowing through the resistance of the core they create heat. As you are aware from the Foundation Course if there is not a complete circuit a current could not flow. Use of Laminations So what can be done to stop the eddy currents in the iron core of the coil? The solution is to make the core of thin strips of insulated iron material called "laminations" and for the lamination not to form a continuous loop around the coil. So a break in the lamination is formed and this small air gap is the necessary break in the circuit and the eddy currents cannot now flow.




